If 1,ω,ω^2 are the cube roots of Unity, then find the roots of the equation(x-1)^3+8=0 #IIT JEE

If 1,ω,ω^2 are the cube roots of Unity, then find the roots of the equation(x-1)^3+8=0 #IIT JEE

If the cube roots of unity are 1,ω,ω^2, then the roots of 〖(x+1)〗^3+8=0 areПодробнее

If the cube roots of unity are 1,ω,ω^2, then the roots of 〖(x+1)〗^3+8=0 are

Solved problems on cube root of unity| Important questions on cube root of unity #iit jee mathsПодробнее

Solved problems on cube root of unity| Important questions on cube root of unity #iit jee maths

If `1,omega,omega^(2)` are the cube roots of unity, then the roots of the equation `(x-1)^(3)+8=0`Подробнее

If `1,omega,omega^(2)` are the cube roots of unity, then the roots of the equation `(x-1)^(3)+8=0`

If the cube roots of unity are 1, ω, ω, then the roots of the equation (x – 1)3+8=0 areПодробнее

If the cube roots of unity are 1, ω, ω, then the roots of the equation (x – 1)3+8=0 are

If the cube roots of unity are `1,w w^2`,then the roots of the equation `(x-1)^3 + 8 =0`, areПодробнее

If the cube roots of unity are `1,w w^2`,then the roots of the equation `(x-1)^3 + 8 =0`, are

If the cube roots of unity are `1,omega,omega^2`, then the roots of the equation `(x-1)^3+8=0`,...Подробнее

If the cube roots of unity are `1,omega,omega^2`, then the roots of the equation `(x-1)^3+8=0`,...

События